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4.9x^2=13.5x
We move all terms to the left:
4.9x^2-(13.5x)=0
We add all the numbers together, and all the variables
4.9x^2-(+13.5x)=0
We get rid of parentheses
4.9x^2-13.5x=0
a = 4.9; b = -13.5; c = 0;
Δ = b2-4ac
Δ = -13.52-4·4.9·0
Δ = 182.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13.5)-\sqrt{182.25}}{2*4.9}=\frac{13.5-\sqrt{182.25}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13.5)+\sqrt{182.25}}{2*4.9}=\frac{13.5+\sqrt{182.25}}{9.8} $
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